Interactive Leanjoe
WARNING: This is the kind of entry that makes my boyfriend stop reading my blog. But I can't help it -- these are the things that consume my thoughts.
I didn't do so well on that test yesterday. I saw it coming a couple days ago, because I realized I hadn't done enough problems. Physics takes a lot of practice (at least for me), but for some reason I insisted on studying for it like I study for chemistry... re-reading chapters and taking notes.
I hate seeing myself fall onto a mediocre part of a curve. It's so discouraging. And now I have to do my physics homework for tomorrow. But who the fuck wants to do that? It's like kissing someone who just spat in your face.
Kind of.
Why is a B so bad, anyway? It's not, right? No. It is. I can't have a B. I can't have a B because I got a C+ in calculus in college and my science GPA needs to be as high as I can possibly make it.
Eww. Premed grade anxiety. Repulsive!
Okay. So maybe you can help me with this. Here's problem #1 from tonight's homework:
"1. Maybe we could make a straight 0.5-mm-diameter copper wire levitate, i.e., just 'float' horizontally in air by passing current through it, because of the force due to the Earth's magnetic field. This field is horizontal, perpendicular to the wire, and of magnitude 0.5G=0.000005 tesla. What current should the wire carry? Does the answer seem practical?"
I love the first three words. Maybe who could? Certainly not me.
So... got any ideas? Post a comment! Seriously. 'Cause I don't want to do this right now.
NOTE: A certain someone has a husband who teaches physics. And if she loves me she could ask him what the fuck I'm supposed to do with the diameter of the wire in that problem. Because I seriously don't have a clue.
ADDENDUM: Okay. So apparently you're supposed to set the force due to gravity equal to the force due to the magnetic field. But the gravitational force = (m)(g), and since the mass isn't given you're supposed to use density of copper = m/v. The volume is the volume of the wire, which is a cylinder and equals pi(radius)squared(length). So now you have the gravitational force = (density of copper)(pi)(radius)squared(length)(g). And you set that all equal to the force of the magnetic field, which equals (the current)(length of the wire)(magnetic field strength). And then you solve for the current. Why am I blogging about this?
I didn't do so well on that test yesterday. I saw it coming a couple days ago, because I realized I hadn't done enough problems. Physics takes a lot of practice (at least for me), but for some reason I insisted on studying for it like I study for chemistry... re-reading chapters and taking notes.
I hate seeing myself fall onto a mediocre part of a curve. It's so discouraging. And now I have to do my physics homework for tomorrow. But who the fuck wants to do that? It's like kissing someone who just spat in your face.
Kind of.
Why is a B so bad, anyway? It's not, right? No. It is. I can't have a B. I can't have a B because I got a C+ in calculus in college and my science GPA needs to be as high as I can possibly make it.
Eww. Premed grade anxiety. Repulsive!
Okay. So maybe you can help me with this. Here's problem #1 from tonight's homework:
"1. Maybe we could make a straight 0.5-mm-diameter copper wire levitate, i.e., just 'float' horizontally in air by passing current through it, because of the force due to the Earth's magnetic field. This field is horizontal, perpendicular to the wire, and of magnitude 0.5G=0.000005 tesla. What current should the wire carry? Does the answer seem practical?"
I love the first three words. Maybe who could? Certainly not me.
So... got any ideas? Post a comment! Seriously. 'Cause I don't want to do this right now.
NOTE: A certain someone has a husband who teaches physics. And if she loves me she could ask him what the fuck I'm supposed to do with the diameter of the wire in that problem. Because I seriously don't have a clue.
ADDENDUM: Okay. So apparently you're supposed to set the force due to gravity equal to the force due to the magnetic field. But the gravitational force = (m)(g), and since the mass isn't given you're supposed to use density of copper = m/v. The volume is the volume of the wire, which is a cylinder and equals pi(radius)squared(length). So now you have the gravitational force = (density of copper)(pi)(radius)squared(length)(g). And you set that all equal to the force of the magnetic field, which equals (the current)(length of the wire)(magnetic field strength). And then you solve for the current. Why am I blogging about this?
Labels: Drew, Katie, Postbacc Program
2 Comments:
i'm siding with drew. can't we get more sex-related entry's? seriously i hope katie's hubby can come to the rescue cuz that shit sounds ridiculously hard. that entry made my head hurt. stop it. i turn to you for entertainment.
Uhhh... Oops. Sorry. I lagged a few days in my blog reading, so I missed the boat on that one. Maybe next time.
Kevin's teaching quantum mechanics this semester. Do you have to take that? It sounds horrible. He's tried to explain it to me several times and it makes my brain feel like it's going to explode. Not good for ye old ego.
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